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  • Dmitriy 168 posts 588 karma points
    Nov 01, 2018 @ 10:12
    Dmitriy
    0

    Get current root node from nested content partial view

    Hello, Umbracians.

    Sometimes website have a lot of root nodes, in multilingual case for example.

    In common, there is no problem to get a current root node with @Model.Ancestor<HomePage>(), but there is when you do it in a partial view of nested content

    I'am confused. How to get a current root node from partial view of nested content?

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  • Alex Skrypnyk 6175 posts 24176 karma points MVP 8x admin c-trib
    Nov 01, 2018 @ 11:52
    Alex Skrypnyk
    100

    Hello Dmitriy

    You can get the current page Id with this code:

    @UmbracoContext.Current.PageId

    And then get current root node with code:

    var currentPage = Umbraco.TypedContent(UmbracoContext.Current.PageId);
var root = currentPage.Ancestor<HomePage>();

    Thanks,

    Alex

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  • Dmitriy 168 posts 588 karma points
    Nov 01, 2018 @ 11:56
    Dmitriy
    0

    Hi, Alex

    Thank you, seems it what I need.

    Is it optimal performance way, or has some leaks?

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  • Alex Skrypnyk 6175 posts 24176 karma points MVP 8x admin c-trib
    Nov 01, 2018 @ 12:03
    Alex Skrypnyk
    1

    It's fine in performance

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  • Garðar Þorsteinsson 119 posts 565 karma points
    Nov 01, 2018 @ 12:19
    Garðar Þorsteinsson
    1

    Hi,

    Would it not be better to use:

        var currentNode = UmbracoContext.Current.PublishedContentRequest.PublishedContent;
    var root = currentNode.Site();
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  • Bjarne Fyrstenborg 1285 posts 4039 karma points MVP 8x c-trib
    Jun 19, 2019 @ 13:00
    Bjarne Fyrstenborg
    2

    Alternative access IPublishedContent via UmbracoHelper - Umbraco property in UmbracoViewPage class.

    var currentNode = Umbraco.AssignedContentItem.Root();
var site = currentNode.Root();

    /Bjarne

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