Hi Simon,

If you want to have the Current page name using the field title you can just do something like this

if(Model.HasValue("title")){
Model.title 
}
else{
Model.Name
 } 

or 

var titlePage = Model.HasValue("title")? Model.title : Model.Name; 
@titlePage

for the parent name

Model.Parent.Name or 

var parentName = Model.Parent.HasValue("title")? Model.Parent.title : Model.Parent.Name;

@parentName 

If I try and use the code you have mentioned in my umbraco template I get the following error:

<h1 class="page-title">
                    @{
                        var parentTitle = Model.Parent.HasValue("title")? Model.Parent.title : Model.Parent.Name;
                    }
                    @parentTitle
                </h1>

CS0119: 'Umbraco.Core.Models.ContentExtensions.Parent(Umbraco.Core.Models.IMedia)' is a 'method', which is not valid in the given context

I have tried using the @Model bit before and I got the same issues; Am I missing a key bit of information or library?

Hang on are you using this code in a template or in a cshtml file ?

If you are using it in a template you need to wrap the code like this

<umbraco:Macro runat="server" language="cshtml">
@using umbraco.MacroEngines;
    @inherits umbraco.MacroEngines.DynamicNodeContext 
@{
var parentTitle = Model.Parent.HasValue("title")? Model.Parent.title : Model.Parent.Name;
 @parentTitle
 }
</umbraco:Macro> 

OK, So I need to use a partial view macro in Umbraco to display code like this? Is that correct?

are you using v6 ? am not very familiar with v6 

I am using Umbraco 6.1.6 and asp.Net MVC + Razor.

I just need a way to show a field form the parent-page on the child page, whether this be in my template or in a partial view. :) Thanks!

Ive put this code in a partial view but it errors as below

@inherits Umbraco.Web.Mvc.UmbracoTemplatePage
@if(!Model.Parent != null){
    <h1>@Model.Parent.Name</h1>
}

Operator '!' cannot be applied to operand of type 'method group'

If anyone's looking to do this, I found Model.Parent.Name wouldn't work, but Model.Content.Parent.Name would

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