how do i list siblings and mark oneself - Templates and document types

hickoryFornander 32 posts 52 karma points

Jan 29, 2010 @ 12:29

How do I list siblings and mark oneself?

Hi! I need help to think :)

I want to create a list of the siblings that exist to a page/node, including itself. When doing this I wish to mark the self-node so that I can add different css to that list object. Is that possible?

Thanks!

/too tired >S

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Thomas Höhler 1237 posts 1709 karma points MVP

Jan 29, 2010 @ 12:34

<xsl:param name="currentPage"/>
<xsl:template match="/">
  <ul>
    <xsl:for-each select="$currentPage/preceding-sibling">
      <li><xsl:value-of select="@nodeName"/></li>
    </xsl:for-each>
    <li><xsl:value-of select="$currentPage/@nodeName"/></li>
    <xsl:for-each select="$currentPage/following-sibling">
      <li><xsl:value-of select="@nodeName"/></li>
    </xsl:for-each>
  </ul>
</xsl:template>

hth, Thomas

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hickoryFornander 32 posts 52 karma points

Jan 30, 2010 @ 04:38

Hi! Thank you so much! Been sleeping some now too and got it almost working :D The only thing missing is the link to the siblings.

<xsl:param name="currentPage"/>
<xsl:template match="/">
<ul id="menuShowSiblings">

<xsl:if test="count($currentPage/preceding-sibling::node) != 0">
    <xsl:for-each select="$currentPage/preceding-sibling::node() [string(data [@alias='hide']) != '1']">
      <li>
    <a href="#"> 
    <xsl:value-of select="string(./data [@alias='pageTitle'])"/>
    </a>
      </li>
    </xsl:for-each>
</xsl:if>

<li><xsl:attribute name="class">active</xsl:attribute>
    <xsl:value-of select="$currentPage/data [@alias='pageTitle']"/>
</li>

<xsl:if test="count($currentPage/following-sibling::node) != 0">
    <xsl:for-each select="$currentPage/following-sibling::node()[string(data [@alias='hide']) != '1']">
      <li>
    <a href="#"> 
    <xsl:value-of select="string(./data [@alias='pageTitle'])"/>
    </a>
    </li>
    </xsl:for-each>
</xsl:if>
</ul>

</xsl:template>

My problem is that I get an xsl parsing error when I add the url to the sibling pages. :S Why?

Thank you! :)

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hickoryFornander 32 posts 52 karma points

Jan 30, 2010 @ 04:53

Hi! Ok, an update....it works to go forward :S. I can add the links to the following-sibling, but not the links to preceding-sibling. So the first page that only show the following-siblings works just fine, but not the rest because they use the preceding-sibling. And it is only with {umbraco.library:NiceUrl(@id)}, any other path works fine. Ehhh...why?

<xsl:param name="currentPage"/>
<xsl:template match="/">


<ul id="menuShowSiblings">

<xsl:if test="count($currentPage/preceding-sibling::node) != 0">
    <xsl:for-each select="$currentPage/preceding-sibling::node() [string(data [@alias='hide']) != '1']">
      <li>
    <a href="#"> 
    <xsl:value-of select="string(./data [@alias='pageTitle'])"/>
    </a>
    </li>
    </xsl:for-each>
</xsl:if>

<li><xsl:attribute name="class">active</xsl:attribute>
    <xsl:value-of select="$currentPage/data [@alias='pageTitle']"/>
</li>

<xsl:if test="count($currentPage/following-sibling::node) != 0">
    <xsl:for-each select="$currentPage/following-sibling::node()[string(data [@alias='hide']) != '1']">
      <li>
    <a href="{umbraco.library:NiceUrl(@id)}">
    <xsl:value-of select="string(./data [@alias='pageTitle'])"/>
    </a>
    </li>
    </xsl:for-each>
</xsl:if>
</ul>

</xsl:template>

Anyone with an idea?

Thank you! :)

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hickoryFornander 32 posts 52 karma points

Jan 30, 2010 @ 08:50

Sorry forgot to write the error message ...dooh! >S

Error parsing the XSLT:

System.OverflowException: Value was either too large or too small for an Int32.
at System.Convert.ToInt32(Double value)
at System.Double.System.IConvertible.ToInt32(IFormatProvider provider)
at System.Convert.ChangeType(Object value, Type conversionType, IFormatProvider provider)
at System.Xml.Xsl.Runtime.XmlQueryRuntime.ChangeTypeXsltArgument(XmlQueryType xmlType, Object value, Type destinationType)
at System.Xml.Xsl.Runtime.XmlQueryContext.InvokeXsltLateBoundFunction(String name, String namespaceUri, IList`1[] args)
at (XmlQueryRuntime {urn:schemas-microsoft-com:xslt-debug}runtime)
at Root(XmlQueryRuntime {urn:schemas-microsoft-com:xslt-debug}runtime)
at Execute(XmlQueryRuntime {urn:schemas-microsoft-com:xslt-debug}runtime)
at System.Xml.Xsl.ExecuteDelegate.Invoke(XmlQueryRuntime runtime)
at System.Xml.Xsl.XmlILCommand.Execute(Object defaultDocument, XmlResolver dataSources, XsltArgumentList argumentList, XmlSequenceWriter results)
at System.Xml.Xsl.XmlILCommand.Execute(Object defaultDocument, XmlResolver dataSources, XsltArgumentList argumentList, XmlWriter writer, Boolean closeWriter)
at System.Xml.Xsl.XmlILCommand.Execute(IXPathNavigable contextDocument, XmlResolver dataSources, XsltArgumentList argumentList, XmlWriter results)
at System.Xml.Xsl.XmlILCommand.Execute(IXPathNavigable contextDocument, XmlResolver dataSources, XsltArgumentList argumentList, TextWriter results)
at System.Xml.Xsl.XslCompiledTransform.Transform(IXPathNavigable input, XsltArgumentList arguments, TextWriter results)
at umbraco.macro.GetXsltTransformResult(XmlDocument macroXML, XslCompiledTransform xslt, Dictionary`2 parameters)
at umbraco.presentation.umbraco.developer.Xslt.xsltVisualize.visualizeDo_Click(Object sender, EventArgs e)

..beautiful huh?!

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Stephan Lonntorp 195 posts 212 karma points

Jan 30, 2010 @ 10:36

And if you check the box "Don't check for errors", when it saves, does it work?

//S

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Chriztian Steinmeier 2800 posts 8790 karma points MVP 8x admin c-trib

Jan 30, 2010 @ 10:41

Hi,

Let's take a different approach - a little more XSLT-ish:

<?xml version="1.0" encoding="utf-8" ?>
<xsl:stylesheet
    version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:umbraco.library="urn:umbraco.library"
    exclude-result-prefixes="umbraco.library"
>

    <xsl:output method="xml" indent="yes" omit-xml-declaration="yes" />

    <xsl:param name="currentPage" />

    <xsl:template match="/">
        <ul id="menuShowSiblings">
            <xsl:apply-templates select="$currentPage/../node" />
        </ul>
    </xsl:template>

    <!-- node template -->
    <xsl:template match="node">
        <li>
            <xsl:if test="$currentPage/@id = @id">
                <xsl:attribute name="class">active</xsl:attribute>
            </xsl:if>
            <a href="{umbraco.library:NiceUrl(@id)}">
                <xsl:value-of select="data[@alias = 'pageTitle']"/>
            </a>
        </li>
    </xsl:template>

    <!-- No output for nodes marked as hidden -->
    <xsl:template match="node[data[@alias = 'umbracoNaviHide'] = 1]" />

</xsl:stylesheet>

This uses a separate template for creating the list item and link; it uses a template to hide items instead of including that long XPath predicate in every select you might add in the future; finally, it applies templates to the parent node's children, instead of manually selecting preceding- and follwing-siblings.

I'd advice you to use the 'standard' alias umbracoNaviHide for hiding nodes, to maximize compatibility with 3rd party packages and such.

If you don't want a link around the $currentPage menuitem, you can use a choose statement, like this inside the template:

   <xsl:choose>
        <xsl:when test="$currentPage/@id = @id">
            <xsl:value-of select="data[@alias = 'pageTitle']" />
        </xsl:when>
        <xsl:otherwise>
            <a href="{umbraco.library:NiceUrl(@id)}">
                <xsl:value-of select="data[@alias = 'pageTitle']" />
            </a>
        </xsl:otherwise>
    </xsl:choose>

/Chriztian

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hickoryFornander 32 posts 52 karma points

Feb 01, 2010 @ 06:55

Hi! Thank you so much for all your answers!!

I tested:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp " "> ]>

<xsl:stylesheet
        version="1.0"
        xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
        xmlns:umbraco.library="urn:umbraco.library"
        exclude-result-prefixes="umbraco.library">

        <xsl:output method="xml" indent="yes" omit-xml-declaration="yes" />

        <xsl:param name="currentPage" />

        <xsl:template match="/">
                <ul id="menuShowSiblings">
            
                        <xsl:apply-templates select="$currentPage/../node [data[@alias = 'hide'] = 0 and (count(./node) > 0)]" />
                </ul>
        </xsl:template>

        
        <xsl:template match="node">
                <li>
            <xsl:choose>
                <xsl:when test="$currentPage/@id = @id">
                    <xsl:attribute name="class">active</xsl:attribute>
                                <xsl:value-of select="data[@alias = 'pageTitle']" />
                        </xsl:when>
                        <xsl:otherwise>
                                <a href="{umbraco.library:NiceUrl(@id)}">
                                        <xsl:value-of select="data[@alias = 'pageTitle']" />
                                </a>
                        </xsl:otherwise>
            </xsl:choose>
                </li>
        </xsl:template>
</xsl:stylesheet>

AND it works! :D Thank you!

I understand that it is better to use the "umbracoNaviHide". But I have a main menu where I do not want these subpages to be seen (there I use "umbracoNaviHide"), and I do not want to be confusing others by saying that it is the opposite for this menu. So a solution I came up with was to check for "hide" here :) I am new to Umbraco so if you have a better suggestion I am very interested in hearing :) It is fun to learn!

Thanks!! :)