tagservice umbraco 7

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Kyle 24 posts 63 karma points

Feb 26, 2014 @ 13:48
0

TagService Umbraco 7

Using Umbraco 7
Hi,

I've been stuck for a bit now trying to find the new alternative for:
```
umbraco.cms.businesslogic.Tags.Tag.GetDocumentsWithTags(tags);
```
This works perfectly it provides me with a list of ID's with the same tags as the current page. I can still use this method but I would like to know the new way :).

I've seen the new TagQuery helper but can't see the equivalent method.

Thanks,

Kyle
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Kyle 24 posts 63 karma points

Aug 19, 2014 @ 16:24
2
Not sure if anyone else had this problem but it seems to be there in 7.1.4
```
Umbraco.TagQuery.GetContentByTag("tags,here")
```
Kyle
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bob baty-barr 1180 posts 1294 karma points MVP

Jan 23, 2015 @ 23:18
3
I am going to post this here... but also try to put it in the wiki or docs or wherever...

here is a code snippet using the tagservice.
```
var tagsFromService = UmbracoContext.Application.Services.TagService.GetAllContentTags("tagGroup");
@foreach(var tag in tagsFromService) {
@tag.Text(@tag.NodeCount)
}
```
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Jeavon Leopold 3072 posts 13628 karma points MVP 10x admin c-trib

Jun 14, 2015 @ 20:33

0

Hello, I just came across this post while searching for a different thread but I have just started a documentation page for Tags here, would love loads more examples using the TagService....

Jeavon

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Lee 1130 posts 3088 karma points

May 09, 2016 @ 11:13
0
What about efficient paging?
```
UmbracoContext.Application.Services.TagService.GetTaggedContentByTag("Category1").Select(x => x.EntityId);
```
This just gets everything... What if you have 10K+ of content with a specific tag.
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Lars Gyrup Brink Nielsen 6 posts 76 karma points

May 31, 2016 @ 17:41

Paging is something like this:

string tag = "Category1";
int pageSize = 10;
int pageNumber =  3;
int pageIndex = pageNumber - 1;

UmbracoContext.Application.Services.TagService
    .Select(x => x.EntityId)
    .GetTaggedContentByTag(tag)
    .Skip(pageIndex * pageSize)
    .Take(pageSize)
    .ToList();

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