Hello Umbraco Community,

I've writen a XSLT to display all my single News Items.
After that i inserted it to my template.

This XSLT should display the single Items like that:

-Header
-Date
-Picture

My problem is that the picture displays the id instead of the picture.
How can I fix this?

I am using Umbraco 7.1.8

This is my XSLT:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet 
    version="1.0" 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns:msxml="urn:schemas-microsoft-com:xslt" 
    xmlns:umbraco.library="urn:umbraco.library" xmlns:Examine="urn:Examine" 
    exclude-result-prefixes="msxml umbraco.library Examine ">

<xsl:output method="xml" omit-xml-declaration="yes"/>

<xsl:param name="currentPage"/>

<xsl:template match="/">

<!-- The fun starts here -->
<ul>
<xsl:for-each select="$currentPage/* [@isDoc and string(umbracoNaviHide) != '1']">
    <a>
        <h2><a href="{umbraco.library:NiceUrl(@id)}">
            <xsl:value-of select="@nodeName"/>
            </a></h2>
          <small class="meta">Posted: <xsl:value-of select="umbraco.library:LongDate(@updateDate, true(), ' - ')"/></small><br/>
          <p class="introduction">
            <xsl:value-of select="umbraco.library:ReplaceLineBreaks(introduction)"/>
          </p>


        <xsl:value-of select="newspicture"/>

    </a>
</xsl:for-each>
</ul>

</xsl:template>

</xsl:stylesheet>

Thank you very much.

Sincerely David :)