Hi Alex,

I think you ask for paging with 5 items per page. For example you can use @foreach (var item in items.Skip((page - 1) * pageSize).Take(pageSize)) to step forward. Below you find an example I use. In your case you should use pageSize = 5;. Good Luck!

@inherits Umbraco.Web.Mvc.UmbracoTemplatePage

@{
        var pageSize =2;
        var page =1;int.TryParse(Request.QueryString["page"],out page);
        var items = CurrentPage.Children.OrderBy("nyhetsdatum descending");
        var totalPages =(int)Math.Ceiling((double)items.Count()/(double)pageSize);

        if(page > totalPages)
        {
                page = totalPages;
        }
        else if(page < 1)
        {
                page =1;
        }
}
<ul class="nyhetslista">
    @foreach (var item in items.Skip((page - 1) * pageSize).Take(pageSize))
    { 
        <ul>
        <li>@item.nyhetsdatum.ToString("d MMMM yyyy")</li>
        <li>@item.huvudrubrik</li>
        <li>@item.underrubrik</li>
        <li>@item.bodyText</li>
        <hr class="line_gradient" />
        <br>
        </ul>
    }
</ul>

@if (totalPages > 1)
    {
        <div class="pagination">
            <div>
                @if (page > 1)
                {
                    <span><a href="?page=@(page-1)">Previous</a></span>
                }
                @for (int p = 1; p < totalPages + 1; p++)
                {
                    var active = (p == page) ? "active" : string.Empty;
                    <span class="@active">
                        <a href="?page=@p">@p</a>
                    </span>
                }
                @if (page < totalPages)
                {
                    <span><a href="?page=@(page+1)">Next</a></span>
                }
            </div>
        </div>
    }