call a partial view with a parameter

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Silvan Egger 28 posts 200 karma points

Feb 24, 2016 @ 08:41
0

Call a Partial View with a Parameter
Hi everyone

I have a document type "Person" and i want to create a partial view, where i can give a dynamic amount of persons, which should then be displayed.

I tried it like this:

My Template:
```
@{
 //i get the persons from the multinode treepicker
 var persons = Umbraco.Content(Umbraco.Field("persons").ToString().Split(','));
}

these persons are involved:

@Html.Partial("showPersons", (DyanmicPublishedContentList)persons)
```
And this is my Partial View:
```
@model DynamicPublishedContentList

<ul>
 @foreach(var person in Model)
 {
 <li>@Model.GetPropertyValue("personPrename") @Model.GetPropertyValue("personSurname")</li>
 }
</ul>
```
I get this error:

Compiler Error Message: CS0246: The type or namespace name 'DynamicPublishedContentList' could not be found (are you missing a using directive or an assembly reference?)

This doesn't work in any Way... I'm looking for a good solution for my case...

I already did it with calling the partial for every person like this:

Template:
```
@Html.Partial("showPerson", (IPublishedContent)leader)
```
Partial View:
```
@model IPublishedContent

@Model.GetPropertyValue("personPrename") @Model.GetPropertyValue("personSurname")
```
But i need to be able to display multiple persons with one partial view for design reasons...

Thanks for your help.

Greets, Silvan
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Ryan 34 posts 138 karma points

Feb 24, 2016 @ 09:00
100
Could you not pass in an IEnumerable of IPublishedContent?

So your partial view will be something like this....
```
@model IEnumerable<IPublishContent>

foreach(var person in Model)
{
 @Model.GetPropertyValue("personPrename") @Model.GetPropertyValue("personSurname")
}
```
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Silvan Egger 28 posts 200 karma points

Feb 24, 2016 @ 09:19

Great! This solved my problem, thanks!

The solution now looks like this

Template

@{
    //I get the persons from the multinode treepicker
    var persons = Umbraco.Content(Umbraco.Field("persons").ToString().Split(','));
}

<p>these persons are involved:</p>

@Html.Partial("showPersons", (IEnumerable<IPublishedContent>)persons)

Partial View

@model IEnumerable<IPublishedContent>

<ul>
    @foreach(var person in Model)
    {
        <li>@person.GetPropertyValue("personPrename")</p>
    }
</ul>

Greets, Silvan

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