reindex single node in v8

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Søren Kottal 712 posts 4570 karma points MVP 6x c-trib

Aug 30, 2019 @ 15:08

0

Reindex single node in v8

Anyone know how to reindex a single node in ExternalIndex in v8?

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Matt Brailsford 4125 posts 22223 karma points MVP 9x c-trib

Aug 30, 2019 @ 15:14

I used to do the following in v7

public static class LuceneHelper
{
    public static void ReindexNode(int id, string indexName, string indexType)
    {
        var xmlStr = umbraco.library.GetXmlNodeById(id.ToString()).Current.OuterXml;
        var xml = XElement.Parse(xmlStr);

        ExamineManager.Instance.IndexProviderCollection[indexName]
            .ReIndexNode(xml, indexType);
    }
}

I'm not sure how you get the XML for a node now in v8, but hopefully it gives you a starting point.

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Remko 118 posts 283 karma points

Aug 30, 2019 @ 15:19
2
Hi,

I simply use this:
```
ExamineManager.Instance.Indexes.FirstOrDefault(i => i.Name == "ExternalIndex")?.IndexItem(new ValueSet(id));
```
where id is string
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Søren Kottal 712 posts 4570 karma points MVP 6x c-trib

Aug 30, 2019 @ 15:46

102

Ooh, didn't know you could just new ValueSet(id)

I got it working by doing index.IndexItems(_valueSetBuilder.GetValueSets(arrayOfIContents));

index is the IIndex, _valueSetBuilder is IPublishedContentValueSetBuilder, and e is coming from the Published event on the content service

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Steve Megson 151 posts 1024 karma points MVP c-trib

Aug 30, 2019 @ 15:59

1

I think you have to do it your way. Unless I'm missing something, new ValueSet(id) will just create an object with that ID and no other fields populated, so indexing that won't do the right thing.

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