get current ipublishedcontent for umbraco 9

Go to solution

Press Ctrl / CMD + C to copy this to your clipboard.

Copied to clipboard

Flag this post as spam?

This post will be reported to the moderators as potential spam to be looked at

Carl Sjöholm 44 posts 327 karma points

Oct 15, 2021 @ 05:31

Umbraco 9

I know how to get current content in Umbraco 8 e.g.

https://our.umbraco.com/forum/umbraco-8/97200-get-current-ipublishedcontent

But how do I get the same context in Umbraco 9?

There is no Current.xxx

I need this in order to handle my custom view models.

namespace UmbracoProject.Core.ViewModels
{
public class LoginViewModel : BaseViewModel
{
    //  CAN'T Pass null
    public LoginViewModel() : base(Current.UmbracoContext.PublishedRequest.PublishedContent)
    {

    }

    public LoginViewModel(IPublishedContent content) : base(content)
    {
    }

    [Display(ResourceType = typeof(TextResource), Name = "Label_EmailAddress")]
    [Required(ErrorMessageResourceType = typeof(TextResource), ErrorMessageResourceName = "Error_Required")]
    [EmailAddress(ErrorMessageResourceType = typeof(TextResource), ErrorMessageResourceName = "Error_EmailAddress")]
    [DataType(DataType.EmailAddress)]
    public string EmailAddress { get; set; }

    [Display(ResourceType = typeof(TextResource), Name = "Label_Password")]
    [Required(ErrorMessageResourceType = typeof(TextResource), ErrorMessageResourceName = "Error_Required")]
    [DataType(DataType.Password)]
    public string Password { get; set; }
}
}

Copy Link

Warren Buckley 2106 posts 4836 karma points MVP ∞ admin hq c-trib

Oct 20, 2021 @ 11:31

Hi Carl 👋

Current is not really a thing anymore in Umbraco V9 and you should use DI to get what you need in the constructor etc...

As you seem to be doing custom view models I suggest you take a look at this piece of documentation.

https://our.umbraco.com/documentation.../Reference/routing/custom-controllers#returning-a-view-with-a-custom-model

So it would be best to use PublishedContentWrapped

public class LoginViewModel : PublishedContentWrapped
{
    // The PublishedContentWrapped accepts an IPublishedContent item as a constructor
    public LoginViewModel(IPublishedContent content, IPublishedValueFallback publishedValueFallback) : base(content, publishedValueFallback)
    {
    }


    [Display(ResourceType = typeof(TextResource), Name = "Label_EmailAddress")]
    [Required(ErrorMessageResourceType = typeof(TextResource), ErrorMessageResourceName = "Error_Required")]
    [EmailAddress(ErrorMessageResourceType = typeof(TextResource), ErrorMessageResourceName = "Error_EmailAddress")]
    [DataType(DataType.EmailAddress)]
    public string EmailAddress { get; set; }

    [Display(ResourceType = typeof(TextResource), Name = "Label_Password")]
    [Required(ErrorMessageResourceType = typeof(TextResource), ErrorMessageResourceName = "Error_Required")]
    [DataType(DataType.Password)]
    public string Password { get; set; }
}

Or alternatively as the documentation extend the partial classes that ModelsBuilder has generated.

I hope this helps you.

Warren 😀

Copy Link

Carl Sjöholm 44 posts 327 karma points

Oct 20, 2021 @ 11:59
100
Hi.

But the constructor must be empty for it to work with serialization and jquery-validate etc.

I managed to solve it by inheriting:
```
public class BaseViewModel : IContentModel
```
And setting my own Content.
Copy Link
is working on a reply...

Please Sign in or register to post replies