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  • Carl Sjöholm 44 posts 327 karma points
    Oct 15, 2021 @ 05:31
    Carl Sjöholm
    0

    Get current IPublishedContent for Umbraco 9

    I know how to get current content in Umbraco 8 e.g.

    https://our.umbraco.com/forum/umbraco-8/97200-get-current-ipublishedcontent

    But how do I get the same context in Umbraco 9?

    There is no Current.xxx

    I need this in order to handle my custom view models.

    namespace UmbracoProject.Core.ViewModels
{
public class LoginViewModel : BaseViewModel
{
    //  CAN'T Pass null
    public LoginViewModel() : base(Current.UmbracoContext.PublishedRequest.PublishedContent)
    {

    }

    public LoginViewModel(IPublishedContent content) : base(content)
    {
    }

    [Display(ResourceType = typeof(TextResource), Name = "Label_EmailAddress")]
    [Required(ErrorMessageResourceType = typeof(TextResource), ErrorMessageResourceName = "Error_Required")]
    [EmailAddress(ErrorMessageResourceType = typeof(TextResource), ErrorMessageResourceName = "Error_EmailAddress")]
    [DataType(DataType.EmailAddress)]
    public string EmailAddress { get; set; }

    [Display(ResourceType = typeof(TextResource), Name = "Label_Password")]
    [Required(ErrorMessageResourceType = typeof(TextResource), ErrorMessageResourceName = "Error_Required")]
    [DataType(DataType.Password)]
    public string Password { get; set; }
}
}
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  • Warren Buckley 2106 posts 4836 karma points MVP 7x admin c-trib
    Oct 20, 2021 @ 11:31
    Warren Buckley
    0

    Hi Carl 👋

    Current is not really a thing anymore in Umbraco V9 and you should use DI to get what you need in the constructor etc...

    As you seem to be doing custom view models I suggest you take a look at this piece of documentation.

    https://our.umbraco.com/documentation.../Reference/routing/custom-controllers#returning-a-view-with-a-custom-model

    So it would be best to use PublishedContentWrapped

    public class LoginViewModel : PublishedContentWrapped
{
    // The PublishedContentWrapped accepts an IPublishedContent item as a constructor
    public LoginViewModel(IPublishedContent content, IPublishedValueFallback publishedValueFallback) : base(content, publishedValueFallback)
    {
    }


    [Display(ResourceType = typeof(TextResource), Name = "Label_EmailAddress")]
    [Required(ErrorMessageResourceType = typeof(TextResource), ErrorMessageResourceName = "Error_Required")]
    [EmailAddress(ErrorMessageResourceType = typeof(TextResource), ErrorMessageResourceName = "Error_EmailAddress")]
    [DataType(DataType.EmailAddress)]
    public string EmailAddress { get; set; }

    [Display(ResourceType = typeof(TextResource), Name = "Label_Password")]
    [Required(ErrorMessageResourceType = typeof(TextResource), ErrorMessageResourceName = "Error_Required")]
    [DataType(DataType.Password)]
    public string Password { get; set; }
}

    Or alternatively as the documentation extend the partial classes that ModelsBuilder has generated.

    I hope this helps you.

    Warren 😀

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  • Carl Sjöholm 44 posts 327 karma points
    Oct 20, 2021 @ 11:59
    Carl Sjöholm
    100

    Hi.

    But the constructor must be empty for it to work with serialization and jquery-validate etc.

    I managed to solve it by inheriting:

    public class BaseViewModel : IContentModel

    And setting my own Content.

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