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I am trying to display the page from which the user submitted the form in my email.
I am using this code
<a> <xsl:attribute name="href"><xsl:value-of select="umbraco.library:NiceUrl($records//pageid)"/></xsl:attribute> <xsl:for-each select="umbraco.library:GetXmlNodeById($records//pageid)/node"> <xsl:value-of select="@nodeName" /> </xsl:for-each> </a>
But I only get an empty link to the node. Is there anything I'm missing?
Aha, shouldn't have that "/node" appended :)
<a> <xsl:attribute name="href"><xsl:value-of select="umbraco.library:NiceUrl($records//pageid)"/></xsl:attribute> <xsl:for-each select="umbraco.library:GetXmlNodeById($records//pageid)"> <xsl:value-of select="@nodeName" /> </xsl:for-each> </a>
Works now.
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Xslt transformed email: Get node name by id
I am trying to display the page from which the user submitted the form in my email.
I am using this code
But I only get an empty link to the node. Is there anything I'm missing?
Aha, shouldn't have that "/node" appended :)
Works now.
is working on a reply...