In a "verbatim" string literal prefixed by @, the \ character isn't special so there's no need to escape it. You can use sampleText = sampleText.Replace(@"\\", @"\"); as you would for replacing any other character.
Here the \ isn't a special character to C#, but it's still a special character in a regex pattern, so you need sampleText = Regex.Replace(sampleText ,@"\\\\", @"\");
I'd prefer the first option since it'll be quicker.
Thanks Buddys for your precious time.
I've tried all these suggestions but didn't get the desired output.
A weird thing that i found upon debugging is the "sampleText" is changed to "abc\\\\\\def" (6 backward slashes)
var sampleText = @"abc\\\def" then it changes to "abc\\\\\\def"
I think you're just seeing escaped strings in the debugger. For example, if a string contains a line break then the debugger will show it as "123\n456". If I do
var sampleText = @"abc\\\def";
var result = sampleText.Replace(@"\\\", @"\");
Console.WriteLine(result);
then I get the expected abc\def in the console, but the debugger will display the value of result as "abc\\def".
Replacing "\\" to "\" in Umbraco
Hi Guys
I'm trying to replace a string "abc\\def" to "abc\def"
I have tried these codes but didn't work..! I'm getting the same text returned!
-)
sampleText = sampleText.Replace(@"\\\", @"\");
-)
sampleText = Regex.Replace(sampleText ,@"\\", @"\");
I've been stuck here for a long time..!!!
Anybody knows the solution..?
Hey Arun,
The backslash is used as an escape character in Regex, so you'd need to double them to match "\"
Depending on your requirements, you probably want to match something more like:
sampleText.Replace(@"\\{2,}", @"\")
Where you are matching 2 or more backslash characters and replacing them. This is a good resource for testing Regex: https://regexr.com/
Cheers, Laura
In a "verbatim" string literal prefixed by
@
, the\
character isn't special so there's no need to escape it. You can usesampleText = sampleText.Replace(@"\\", @"\");
as you would for replacing any other character.Here the
\
isn't a special character to C#, but it's still a special character in a regex pattern, so you needsampleText = Regex.Replace(sampleText ,@"\\\\", @"\");
I'd prefer the first option since it'll be quicker.
Thanks Buddys for your precious time.
I've tried all these suggestions but didn't get the desired output.
A weird thing that i found upon debugging is the "sampleText" is changed to "abc\\\\\\def" (6 backward slashes)
var sampleText = @"abc\\\def"
then it changes to "abc\\\\\\def"
among this
sampleText.Replace(@"\\\", @"\")
returns a nearly output abc\\def.
~Arun
I think you're just seeing escaped strings in the debugger. For example, if a string contains a line break then the debugger will show it as
"123\n456"
. If I dothen I get the expected
abc\def
in the console, but the debugger will display the value ofresult
as"abc\\def"
.is working on a reply...