Hello everyone!

I am a developer coding a solution where i want to check if a Member is also a User/backoffice user and add support for our logging. the code looks like this.

public bool AddAndOrLoginMember()
    {
        bool succeeded = false;
        var user = GetUser();
        if (!CheckValidAbonnemang(user))
        {
            return false;
        }

        var memberService = Current.Services.MemberService;

        _logger.Info<LoginService>("Check if user already exists");
        IMember member = memberService.GetByUsername(user.Personnummer);

        var backOfficeUserService = Current.UmbracoContext.Security.CurrentUser;
        if (member != null)
        {
            _logger.Info<LoginService>($"User, {user.Fornamn} {user.Efternamn}: Username {user.Personnummer.Substring(0, 10)}, exists. Login user.");

            // Member already added. Login member
            succeeded = Login(member);
        }
        else
        {
            // Create the user
            member = AddUmbracoMember(user);

            // Login user
            _logger.Info<LoginService>("Login user");
            succeeded = Login(member);
        }

        if (succeeded)
        {
            _logger.Info<LoginService>($"Set forms authentication cookie");
            FormsAuthentication.SetAuthCookie(member.Username, true);
        }

        _logger.Info<LoginService>($"User login succeeded: {succeeded}");

        return succeeded;
    }

I found Current.UmbracoContext.Security.CurrentUser; and it has a method i think called IsAdmin() but it only takes a IUser and when i get the current member its a IMember so it aint compatible.

My first thought was to do something like If()member != null || backOfficeUserService.IsAdmin(member){...} but then i get a "Severity Code Description Project File Line Suppression State Error CS1501 No overload for method 'IsAdmin' takes 1 argument"

so any idea how to easily solve this and do a check if a member is also a backofficeUser? if more clarification is needed i will try to answer it :)