the name request does not exist in the current context - Using Umbraco And Getting Started

Go to solution

Press Ctrl / CMD + C to copy this to your clipboard.

Copied to clipboard

Flag this post as spam?

This post will be reported to the moderators as potential spam to be looked at

Peter van Geffen 54 posts 290 karma points

Oct 25, 2022 @ 08:39

The name 'Request' does not exist in the current context

Using Umbraco And Getting Started

Umbraco 9

We have in our old Umbraco (v8) a 'GetSocialMeta' partial. Obviously it won't work in our new Umbraco (v10) projects.

This is the code:

@inherits Umbraco.Web.Mvc.UmbracoViewPage
@{
    string title = String.Empty;
    string hyperlink = String.Format("https://{0}{1}", Request.Url.Host, Request.Url.AbsolutePath);
    string ogImageUrl = String.Empty;
    string twitterName = String.Empty;
    string canonicalURL = String.Empty;
    string omschrijving = String.Empty;
    string twitterTitle = String.Empty;
}
@if (Model.HasValue("canonicalURL")){
    canonicalURL = Model.Value<string>("canonicalURL");
}
else{
    canonicalURL = @hyperlink;
}
@if (Model.HasValue("browserTitle")){
    title = Model.Value<string>("browserTitle");
}else if (Model.HasValue("paginaTitel")){
    title = Model.Value<string>("paginaTitel");
}else{
    title = Model.Name;
}
@if (Model.Value<string>("twitterNaam", fallback: Fallback.ToAncestors) != String.Empty){
    twitterName = Model.Value<string>("twitterNaam", fallback: Fallback.ToAncestors);
}
@if (Model.Value<IPublishedContent>("ogImage", fallback: Fallback.ToAncestors) != null){
    IPublishedContent ogImage = Model.Value<IPublishedContent>("ogImage", fallback: Fallback.ToAncestors);
    ogImageUrl = String.Format("http://{0}{1}", Request.Url.Host, ogImage.Url);
}else{
    ogImageUrl = String.Format("http://{0}/images/logo-fb.png", Request.Url.Host);
}
@if (Model.HasValue("twitterTitel")){
    twitterTitle = Model.Value<string>("twitterTitel");
}else{
    twitterTitle = title; 
}
@if (Model.HasValue("omschrijving")){
    omschrijving = Model.Value<string>("twitterOmschrijving");
}else{
    omschrijving = Model.Value<string>("metaDescription");
}
@{ 
    <meta property="og:title" content="@title" />
    <meta property="og:type" content="website" />
    <meta property="og:url" content="@hyperlink" />
    <meta property="og:image" content="@ogImageUrl" />
    <meta property="og:description" content="@omschrijving" />
    <meta name="twitter:site" content="@twitterName" />
    <meta name="twitter:creator" content="@twitterName" />
    <meta name="twitter:card" content="summary_large_image" />
    <meta name="twitter:title" content="@twitterTitle" />
    <meta name="twitter:description" content="@omschrijving">
    <meta name="twitter:image" content="@ogImageUrl" />
    <link rel="canonical" href="@canonicalURL">
}

These are the errors we get: An error occurred during the compilation of a resource required to process this request. Please review the following specific error details and modify your source code appropriately.

The name 'Request' does not exist in the current context
+
    string hyperlink = String.Format("https://{0}{1}", Request.Url.Host, Request.Url.AbsolutePath);
The name 'Request' does not exist in the current context
+
    string hyperlink = String.Format("https://{0}{1}", Request.Url.Host, Request.Url.AbsolutePath);
The name 'Request' does not exist in the current context
+
    ogImageUrl = String.Format("http://{0}{1}", Request.Url.Host, ogImage.Url);
The name 'Request' does not exist in the current context
+
    ogImageUrl = String.Format("http://{0}/images/logo-fb.png", Request.Url.Host);

Is there a way to fix this or a better way to set it up?

Copy Link

Huw Reddick 1740 posts 6102 karma points MVP c-trib

Oct 25, 2022 @ 10:37

0

try Context.Request

Copy Link
Huw Reddick 1740 posts 6102 karma points MVP c-trib

Oct 25, 2022 @ 10:39

0

although in .net core there is no Request.url.Host , it is just Request.Host

Copy Link
Peter van Geffen 54 posts 290 karma points

Oct 25, 2022 @ 10:45

0

It unfortunately still returns the same errors

Copy Link
Huw Reddick 1740 posts 6102 karma points MVP c-trib

Oct 25, 2022 @ 14:52
0
just noticed
```
@inherits Umbraco.Web.Mvc.UmbracoViewPage
```
That is not correct for Umbraco 9, IIRC it should be
```
Umbraco.Cms.Web.Common.Views.UmbracoViewPage
```
Copy Link
Peter van Geffen 54 posts 290 karma points

Oct 26, 2022 @ 05:22

0

You're right about that. But it isn't the solution

Copy Link
Huw Reddick 1740 posts 6102 karma points MVP c-trib

Oct 26, 2022 @ 07:46

0

not sure why, works ok for me

Copy Link
Peter van Geffen 54 posts 290 karma points

Oct 26, 2022 @ 07:53

0

Probably because i'm a pretty noob in back-end coding. I've no idea how to get this work in our code (above)

Copy Link
Huw Reddick 1740 posts 6102 karma points MVP c-trib

Oct 26, 2022 @ 10:06
100
I'm not sure either as it just works for me. I just did a quick test and created a partialView as below
```
@inherits UmbracoViewPage
@{

    string hyperlink = String.Format("https://{0}{1}", Context.Request.Host, Context.Request.Path);

}
```
I then included it in my main page @await Html.PartialAsync("Layout/_TestPartial") and it works with no errors
Copy Link
Peter van Geffen 54 posts 290 karma points

Oct 26, 2022 @ 12:29
0
This works indeed. But how do i get it to work for:
```
ogImageUrl = String.Format("http://{0}{1}", Request.Url.Host, ogImage.Url);
```
&
```
ogImageUrl = String.Format("http://{0}/images/logo-fb.png", Request.Url.Host);
```
Because if i adjust it the same way it still won't work
Copy Link
Huw Reddick 1740 posts 6102 karma points MVP c-trib

Oct 26, 2022 @ 12:36

0

just replace Request.Url.Host with Context.Request.Host

Copy Link

Peter van Geffen 54 posts 290 karma points

Oct 26, 2022 @ 12:45

I was too quick with my reply (deleted) Just replace them gives me other errors

Argument 1: cannot convert from 'string' to 'System.IFormatProvider?'
+
    ogImageUrl = String.Format("http://{0}{1}", Context.Request.Host, ogImage.Url);
Argument 2: cannot convert from 'Microsoft.AspNetCore.Http.HostString' to 'string'
+
    ogImageUrl = String.Format("http://{0}{1}", Context.Request.Host, ogImage.Url);
Argument 3: cannot convert from 'method group' to 'object?'
+
    ogImageUrl = String.Format("http://{0}{1}", Context.Request.Host, ogImage.Url);

Copy Link

Huw Reddick 1740 posts 6102 karma points MVP c-trib

Oct 26, 2022 @ 12:51

100

I think it may need to be ogImage.Url() not ogImage.Url

Copy Link
Peter van Geffen 54 posts 290 karma points

Oct 26, 2022 @ 13:01

0

Ah f*ck, that's it. I still have to get used to that extra () compared to Umbraco 8.

Thanks for your help and above all patience.

Copy Link
Peter van Geffen 54 posts 290 karma points

Oct 26, 2022 @ 13:02

0

Up to the next problem :P

Copy Link
Huw Reddick 1740 posts 6102 karma points MVP c-trib

Oct 26, 2022 @ 13:33

1

Happy to help :) had to go through the same pain myself :D

Copy Link
is working on a reply...

Please Sign in or register to post replies