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Asad Kizzie 28 posts 158 karma points

Apr 20, 2023 @ 16:08
0

Macro that Loops Through Media Node "N" Times and Prints
I have a working macro that asks the user to select a node from the media library and then it displays the title of each file within the node.

I have a new need to only display the most recent 5 files within the node, not all of them.

I'm new to XSLT and I'm having trouble with how to create this loop.

Here's what I currently have (that displays all items):
```
<xsl:template match="/">

<ul>
    
        <xsl:for-each select="$documents">
    <xsl:sort select="./@createDate" order="descending" />
        <xsl:if test="number(current()/data [@alias='umbracoBytes']) &gt; 0">
                    <li><a href="{current()/data [@alias='umbracoFile']}"><xsl:value-of select="./@nodeName"/></a> 
            </li>
        </xsl:if>
        </xsl:for-each>
</ul>
```
Any help or suggestions?!
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Jan Skovgaard 11280 posts 23678 karma points MVP 11x admin c-trib

Apr 21, 2023 @ 05:56

Hi Asad

While it's been a while forgive me if my memory is wrong but I think you need to write something like

<xsl:if test="position() < 6"></xsl:if> to only have top 5 recent nodes. So your example would look like this

<xsl:template match="/">

<ul>
    <!-- Loop through nodes and show all -->
        <xsl:for-each select="$documents">
    <xsl:sort select="./@createDate" order="descending" />
        <xsl:if test="position() &lt; 6">
                    <li><a href="{current()/data [@alias='umbracoFile']}"><xsl:value-of select="./@nodeName"/></a> 
            </li>
        </xsl:if>
        </xsl:for-each>
</ul>

Does this work for you?

/Jan

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Asad Kizzie 28 posts 158 karma points

Apr 27, 2023 @ 15:20

0

By golly, I knew it was something simple! Thank you. This worked perfectly.

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Macro that Loops Through Media Node "N" Times and Prints