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  • Simon 81 posts 184 karma points
    Jun 05, 2017 @ 17:31
    Simon
    0

    How to get an item's UDI without hitting the database?

    Hi,

    Trying to find how to get an items unique identifier - used to be an integer but now an Umbraco formatted string e.g. umb://document/4fed18d8c5e34d5e88cfff3a5b457bf2

    I have an Author/Content set up and store the Author as a ContentPicker2 - which stores the item as the new UDI. However, I now have an Examine index set up to look at my Author property.

    On the Author Profile page, I use this Examine Index to find the content attributed to that Author. How can I find the UDI of the Author's page to then pass to Examine?

    Please let me know if what you propose requires a trip to the database as I'd prefer to avoid as many of those as possible!

    Thanks Simon

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  • Alex Skrypnyk 6175 posts 24186 karma points MVP 8x admin c-trib
    Jun 10, 2017 @ 00:28
    Alex Skrypnyk
    1

    Hi Simon

    Past days this code helped me a lot to get udi of iPublishedContent:

     var modelWithKey = Model.Content.Unwrap() as IPublishedContentWithKey;
 var key = modelWithKey.GetKey();
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  • Simon 81 posts 184 karma points
    Jun 17, 2017 @ 18:23
    Simon
    0

    Thanks Alex - great solution!

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  • Andy Robinson 9 posts 96 karma points c-trib
    Jun 26, 2017 @ 13:28
    Andy Robinson
    3

    I needed to do this on an APIController perceptive, discovered this today that seems to format the UDI properly, including getting rid of those pesky dashes from the guid

    IPublishedContent page =  _helper.UmbracoContext.ContentCache.GetById(1156);

var udi = new GuidUdi("document", Model.Content.GetKey());

    Ref: https://our.umbraco.org/apidocs/csharp/api/Umbraco.Core.GuidUdi.html

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  • David Armitage 510 posts 2081 karma points
    Sep 02, 2021 @ 10:53
    David Armitage
    1

    Hi,

    Here is how I do it

     Udi.Create(Constants.UdiEntityType.Document, "the guild key here")
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