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  • Martin 278 posts 661 karma points
    Feb 22, 2018 @ 14:55
    Martin
    0

    Color Picker - Return Label Value

    Hi All,

    Is it possible to return the Color Picker label value?

    Thanks

    Martin

  • David Peck 650 posts 1764 karma points c-trib
    Feb 22, 2018 @ 16:11
    David Peck
    0

    I bet you could using one or more of the DataTypeService. However you'll then be hitting the database, so if you're looking to do this on a page view I would find another route.

  • Mar 07, 2019 @ 22:26
    Abuabdellah | Biker | Umbracian | Freelancer | PPH.me/abuabdellah
    0

    Martin, peace be upon those who follow guidance. I was able to get the label of selected value by using the following code.

    @inherits Umbraco.Web.Mvc.UmbracoTemplatePage
    @using Umbraco.Core.PropertyEditors.ValueConverters;
    @using ContentModels = Umbraco.Web.PublishedContentModels;
    @{
        Layout = null;
    }
    @{
        var hexColor = Umbraco.Field("themeColor");
        String colorLabel = Model.Content.GetPropertyValue<ColorPickerValueConverter.PickedColor>("themeColor").Label;
    }
    

    Preview: enter image description here

  • Matthew Taylor 11 posts 85 karma points
    Jul 31, 2019 @ 13:14
    Matthew Taylor
    1

    This will work for Umbraco 8

            @if (Model.HasValue("yourColorPickerProperty"))
            {
                @* Include this after @inherits Umbraco.Web.Mvc.UmbracoViewPage on your Partial View *@
                @* @using Umbraco.Core.PropertyEditors.ValueConverters; *@
    
                var Colour = "#" + Model.Value<ColorPickerValueConverter.PickedColor>("yourColorPickerProperty");
                var Label = Model.Value<ColorPickerValueConverter.PickedColor>("yourColorPickerProperty").Label;
    
                <p style="color: @Colour">
                    The colour is @Label
                </p>
            }
    
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