using random items in a slider

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Mark Watson 118 posts 384 karma points

Mar 27, 2019 @ 06:35
0

Using random items in a slider
Does anyone know a better way to do the following?

I am trying to use 3 different random testimonials in a slider but not sure how to get three different random items and render them in the right
.

@{ var FirstTestimonial = Model.Content.Site().FirstChild("Testimonial").Children().RandomOrder().FirstOrDefault(); var SecondTestimonial = Model.Content.Site().FirstChild("Testimonial").Children().RandomOrder().FirstOrDefault(); var ThirdTestimonial = Model.Content.Site().FirstChild("Testimonial").Children().RandomOrder().FirstOrDefault();
@renderTestimonial(FirstTestimonial)

@renderTestimonial(SecondTestimonial)

@renderTestimonial(ThirdTestimonial)
}

This works but sometimes I get 2 items the same. I would like each testimonial to be different but random.
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Ronak Panchal 71 posts 230 karma points

Mar 27, 2019 @ 07:30

0

Hello Mark Watson,

As per your code, it's true that you get the same items.

First, take a list of the random item up to 3 then through looping you can display that 3 random items you don't need to take three variable like FirstTestimonial, SecondTestimonial and ThirdTestimonial Just one variable is fine for that.

Regards, Ronak Panchal

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Rhys Hamilton 140 posts 942 karma points

Mar 27, 2019 @ 10:26
100
As Ronak pointed out, you probably don't need to have three separate variables for this.

The following code should work:
```
var testimonials = Model.Content.Site().FirstChild("Testimonial").Children().RandomOrder().Take(3);

foreach (var testimonial in testimonials)
{
    @renderTestimonial(testimonial)
}
```
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Mark Watson 118 posts 384 karma points

Mar 27, 2019 @ 22:23
0
Thanks for the replys but unfortunately the slider is control by script and I need to place the results in the controlling divs. Without the div class "active item" and the following div classes "item" this does not work.
```
<div class="carousel-inner">
<div class="active item">
@renderTestimonial(FirstTestimonial)
</div>
<div class="item">
    @renderTestimonial(SecondTestimonial)
</div>
<div class="item">@renderTestimonial(ThirdTestimonial)
</div>
```
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Rhys Hamilton 140 posts 942 karma points

Mar 28, 2019 @ 10:43

In your code, the first item is active, and the rest are not.

Using this logic, you could refactor your code, using a single variable (instead of 3) and still produce your expected output by using a counter to determine which items in your testimonials should have the "active" class.

For example, like so:

@{
    var testimonials = Model.Content.Site().FirstChild("Testimonial").Children().RandomOrder().Take(3);
    var counter = 1;

    <div class="carousel-inner">
        @foreach (var testimonial in testimonials)
        {
            // If the counter is equal to 1, then set the item class to active
            var isActive = counter == 1 ? "active item" : "";

            <div class="@isActive item">
                @renderTestimonial(testimonial)
            </div>

            // Increment the counter, so you can't have two active items at a time
            counter++;
        }
    </div>
}

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Nik 1614 posts 7260 karma points MVP 7x c-trib

Mar 28, 2019 @ 12:03
2
Rhy's solution is nice, but instead of using a counter you could use a Boolean to track if this is the first iteration when using a foreach loop.

eg:
```
var isFirst = true;

<div class="carousel-inner">
    @foreach(var testimonial in testimonials)
    {
           <div class="@(isFirst ? "active item" : "item")">
              @renderTestimonial(testimonial)
           </div>

           if(isFirst){isFirst = false;}
    }
</div>
```
Personally, I find this easier to read than having a counter that's increment all the time. If you need the counter for something else however then I'd go down that route :-)

(It comes down to personal preference here I think, just thought it worth sharing the alternative)
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Mark Watson 118 posts 384 karma points

Apr 10, 2019 @ 05:13

1

Thanks Rhys and Nik

Both worked perfectly.

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