Hi all,

I'm trying to customize the Blog 4 Umbraco archive post list, which appears on the right hand side of the blog posts list. On install the archive list show other post as a UL and LI list indented.

I'm trying to configure this as:

Month Year

Post Title

Post Date

Blog 4 Umbraco stores blog posts in a Blog document type, then year, month and day document types. I'm struggling to think how to get the XSLT to parse the folders by month, this is what I have so far:

<xsl:for-each select="$currentPage/ancestor-or-self::node [@nodeTypeAlias = 'Blog']/node [@nodeTypeAlias = 'DateFolder']">
        <xsl:sort select="@nodeName" data-type="number" order="descending" />
        <xsl:for-each select="./node [@nodeTypeAlias = 'DateFolder']">
          <xsl:sort select="@nodeName" data-type="number" order="descending" />
          <!--<li class="month">-->
            <xsl:variable name="monthname" select="umbraco.library:FormatDateTime(concat(./../@nodeName,'-',@nodeName,'-11T10:24:46'),'MMMM yyyy')" />
            <a class="archive-date-link" href="{umbraco.library:NiceUrl(@id)}">
                <xsl:value-of select="$monthname"/>
            </a>
        &nbsp;
        <span>
        <br />
        <div style="color:#fff;">
            <a style="color:#fff;text-decoration:none;">
                <xsl:attribute name="href">
                    <xsl:value-of select="umbraco.library:NiceUrl($currentPage/ancestor-or-self::node/node/node/node/node/@id)" />
                </xsl:attribute>
                <xsl:value-of select="$currentPage/ancestor-or-self::node/node/node/node/node/@nodeName" />
            </a>
        </div>

        <div>

        </div>

        <div style="color:#999;">
            <xsl:value-of select="umbraco.library:FormatDateTime($currentPage/node/node/node/node/@createDate, 'dd/MM/yyy')"/>
        </div>
              <!-- (<xsl:value-of select="count(.//node [@nodeTypeAlias = 'BlogPost'])"/>) -->
            </span>

        <div class="blog-separator"><!-- --></div>

          <!--</li>-->
        </xsl:for-each>
      </xsl:for-each>

Any help you could give would be appreciated.