i got it working by using this xslt script:
<xsl:for-each select="umbraco.library:GetXmlNodeById(1074)/NewsItem">

is this possible without using a fix Id?

So for example by selecting the root node of my news items. This is called "News"

Thanks

Hi Dominik

You should be able to fetch the XSLT by doing like this

<xsl:variable name="newsRoot" select="$currentPage/ancestor-or-self::News" />

<xsl:for-each select="$newsRoot/NewsItem>

Does this work for you?

/Jan

Hi Jan,

Your script is not working :(

If i am using "follwing::News" it works but i think this will not work if i try to reach news from a sublevel.

Any solutions?

When you create your XSLT file, select "List Sub Pages From A Changeable Source" from the "Choose a template" drop-down menu in the Create dialogue window. Then you open the Macro for this new XSLT file, go to the "Parameters" tab and:

• enter "source" as the alias
• enter source" as the name
• choose "contentPicker" from the "Type" drop-down
• click the Save button.

Then go to "Settings: and select the template you want to add the XSLT to. When you add the XSLT to the template you will be asked to choose the source from which you want to display sub-pages, in your case News.

Hi Dominik

Hmm, try this instead <xsl:variable name="globalLinksRoot" select="$currentPage/ancestor-or-self::*[@isDoc]/News" />

/Jan

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