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here is my css menu which i wnat to convert in xslt but problem is that the sub menu not display
here is my css menu
<div id="navigation"> <ul><li id='active'> <a href='/index.html'>Home</a></li> <li id='pg916406283472444280'> <a href='/about-us.html'>About Us</a> <div class='wsite-menu-wrap' style='display:none'> <ul class='wsite-menu'> <li id='wsite-nav-863485395226581217'> <a href='/southeast-greenway-campaign-summary.html'> <span class='wsite-menu-title'>Southeast Greenway Campaign Summary</span></a></li> <li id='wsite-nav-611646911499402343'><a href='/faqs.html'> <span class='wsite-menu-title'>FAQs</span></a></li></ul></div>
</div>
here is my xslt code
<xsl:output method="html" omit-xml-declaration="yes"/><xsl:param name="currentPage"/><xsl:template match="/"><!-- start writing XSLT --> <!--<div class='wsite-menu-wrap' style='display:none'>--> <ul > <xsl:for-each select="$currentPage/ancestor-or-self::*/* [string(umbracoNaviHide) != '1' and @level = 2 ]"> <li > <span class="wsite-menu-title"> <xsl:if test="$currentPage/@id=@id or ($currentPage/@parentID=@id) or ($currentPage/parent::*/@parentID=@id)"> <xsl:attribute name="class">wsite-menu-wrap</xsl:attribute> </xsl:if> <strong> <a> <xsl:attribute name="href"><xsl:value-of select="umbraco.library:NiceUrl(@id)"/></xsl:attribute> <xsl:value-of select="@nodeName" /> </a> </strong> <!-- <xsl:if test="count(child::* [string(umbracoNaviHide) != '1' and @level <= 7 ]) > 0"> <div class="navigation" style=""> <xsl:call-template name="Subchild"> </xsl:call-template> </div> </xsl:if>--> </span> </li> </xsl:for-each></ul> <!--</div>--> </xsl:template> <xsl:template name="Subchild"> <xsl:if test="count(child::* [string(umbracoNaviHide) != '1' and @level <= 7 ]) > 0"> <!-- <div class='wsite-menu-wrap' style='display:none'>--> <ul class="wsite-menu" > <xsl:for-each select="child::* [string(umbracoNaviHide) != '1' and @level <= 7 ]"> <li > <span class="wsite-menu-title"> <xsl:if test="$currentPage/@id=@id or ($currentPage/@parentID=@id) or ($currentPage/parent::*/@parentID=@id)"> <xsl:attribute name="class">wsite-menu-wrap</xsl:attribute> </xsl:if> <a> <xsl:attribute name="href"> <xsl:value-of select="umbraco.library:NiceUrl(@id)"/> </xsl:attribute> <xsl:value-of select="@nodeName"/> </a> <xsl:call-template name="Subchild"> </xsl:call-template> </span> </li> </xsl:for-each> </ul> <!-- </div>--> </xsl:if></xsl:template></xsl:stylesheet>
Hi, think this could be in the wrong place. This need to be in the xslt forum :). Could you explain what is wrong?
What is currently happening and what is currently rendering
What you would like to happend and what you would like to render
My xslt problem is that my submenu not display
is working on a reply...
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problem in xslt menu display
here is my css menu which i wnat to convert in xslt but problem is that the sub menu not display
here is my css menu
<div id="navigation">
<ul><li id='active'>
<a href='/index.html'>Home</a></li>
<li id='pg916406283472444280'>
<a href='/about-us.html'>About Us</a>
<div class='wsite-menu-wrap' style='display:none'>
<ul class='wsite-menu'>
<li id='wsite-nav-863485395226581217'>
<a href='/southeast-greenway-campaign-summary.html'>
<span class='wsite-menu-title'>Southeast Greenway Campaign Summary</span></a></li>
<li id='wsite-nav-611646911499402343'><a href='/faqs.html'>
<span class='wsite-menu-title'>FAQs</span></a></li></ul></div>
</div>
here is my xslt code
<xsl:output method="html" omit-xml-declaration="yes"/>
<xsl:param name="currentPage"/>
<xsl:template match="/">
<!-- start writing XSLT -->
<!--<div class='wsite-menu-wrap' style='display:none'>-->
<ul >
<xsl:for-each select="$currentPage/ancestor-or-self::*/* [string(umbracoNaviHide) != '1' and @level = 2 ]">
<li >
<span class="wsite-menu-title">
<xsl:if test="$currentPage/@id=@id or ($currentPage/@parentID=@id) or ($currentPage/parent::*/@parentID=@id)">
<xsl:attribute name="class">wsite-menu-wrap</xsl:attribute>
</xsl:if>
<strong>
<a>
<xsl:attribute name="href"><xsl:value-of select="umbraco.library:NiceUrl(@id)"/></xsl:attribute>
<xsl:value-of select="@nodeName" />
</a>
</strong>
<!-- <xsl:if test="count(child::* [string(umbracoNaviHide) != '1' and @level <= 7 ]) > 0">
<div class="navigation" style="">
<xsl:call-template name="Subchild">
</xsl:call-template>
</div>
</xsl:if>-->
</span>
</li>
</xsl:for-each>
</ul>
<!--</div>-->
</xsl:template>
<xsl:template name="Subchild">
<xsl:if test="count(child::* [string(umbracoNaviHide) != '1' and @level <= 7 ]) > 0">
<!-- <div class='wsite-menu-wrap' style='display:none'>-->
<ul class="wsite-menu" >
<xsl:for-each select="child::* [string(umbracoNaviHide) != '1' and @level <= 7 ]">
<li >
<span class="wsite-menu-title">
<xsl:if test="$currentPage/@id=@id or ($currentPage/@parentID=@id) or ($currentPage/parent::*/@parentID=@id)">
<xsl:attribute name="class">wsite-menu-wrap</xsl:attribute>
</xsl:if>
<a>
<xsl:attribute name="href">
<xsl:value-of select="umbraco.library:NiceUrl(@id)"/>
</xsl:attribute>
<xsl:value-of select="@nodeName"/>
</a>
<xsl:call-template name="Subchild">
</xsl:call-template>
</span>
</li>
</xsl:for-each>
</ul>
<!-- </div>-->
</xsl:if>
</xsl:template>
</xsl:stylesheet>
Hi, think this could be in the wrong place. This need to be in the xslt forum :). Could you explain what is wrong?
What is currently happening and what is currently rendering
What you would like to happend and what you would like to render
My xslt problem is that my submenu not display
is working on a reply...