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  • snorlaks 3 posts 23 karma points
    Feb 22, 2010 @ 13:26
    snorlaks
    0

    remeber class in menu

    Hi,

     

    Im using sample menu from tutorials. It is created dynamibally by xslt macro- normal ul li. I also use css which has different class for actual menu element. Named for example current-element.

     

    Problem is that I dont know how can I tell application which menu element is actual and chould have different css class so that it can be rendered in another way.

     

    Using simple Asp.Net I could store that information in viewstate or just send it with post and so on.

     

    thanks for help

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  • dandrayne 1138 posts 2262 karma points
    Feb 22, 2010 @ 13:31
    dandrayne
    0

    Hi Snorlaks

    If I understand your question correctly, you can find the current page (or current parents)  with something like below

    <xsl:for-each select="$currentPage/node">
      <li>
            <xsl:if test="$currentPage/ancestor-or-self::node/@id = current()/@id">
             <xsl:attribute name="class">current</xsl:attribute>
           </xsl:if> 
      </li>
    </xsl:for-each>

    If it's only the "actual" current page you want, it would be something like

    $currentPage/@id = current()/@id

    Hope this helps,
    Dan

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  • snorlaks 3 posts 23 karma points
    Feb 22, 2010 @ 14:13
    snorlaks
    0

    This is excactly what I was looking for.

     

    Thank You very much for help.

     

    By the way where did You learn how to use xslt in umbraco ?

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  • dandrayne 1138 posts 2262 karma points
    Feb 22, 2010 @ 14:19
    dandrayne
    0

    No problem, glad you got it sorted.

    For xslt in umbraco, I'd start with http://umbraco.org/documentation/books/xslt-basics and looking at the macros in http://our.umbraco.org/projects/business-website-starter-pack or http://our.umbraco.org/projects/creative-website-starter-(cws). ; You may learn to love it!

    Dan

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