In XSLT or?

If yes, then something like this should do it (from the top of my head):

<xsl:for-each select="$currentPage/node">

<xsl:sort select="@createDate" order="descending" />

<xsl:value-of select="@nodeName" />

</xsl:for-each>

I think that would work, but I need to do this in code :)

If you wanna do it in code behind I think this is the way to do it. If there is a better way please let me know!

Node parent = new Node(1070);
Node[] nodes = new Node[parent.Children.Count];
for (int i = 0; i < nodes.Length; i++)
    nodes[i] = parent.Children[i];

Array.Sort(nodes, delegate(Node node1, Node node2) {
    return node1.SortOrder.CompareTo(node2.SortOrder);
});

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