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  • mfeola 117 posts 221 karma points
    May 16, 2012 @ 19:45

    General XSLT for display

    I have been trying to create a general XSLT to display all the content of the datatype by passing in the name of the field it uses in umbraco but so far it isn't displaying anything. 

    I don't really know what to do with this, i can pass in the name, i can pass in a field of a different datatype but i can't seem to pass in this data type and have the foreach loop run through all the parts of this field. what is wrong with this?

    <umbraco:Macro Field="[#list1]" Alias="CheckLists" runat="server"></umbraco:Macro>
    <umbraco:Macro Field="[#list2]" Alias="CheckLists" runat="server"></umbraco:Macro>
    <xsl:param name="ListField" select="/macro/Field"/>
    <xsl:param name="currentPage"/>
    <xsl:template match="/">
      <div id="test">
        <xsl:for-each select="$ListField/data/item">
          <p><xsl:value-of select="listitem" /></p>
  • mfeola 117 posts 221 karma points
    May 16, 2012 @ 20:51

    and i do know that this foreach code WILL display the list items:

    <xsl:for-each select="$currentPage/Field/data/item">

    but that doesn't help when i have multiple embedded content fields on a single page and i want to just use one macro to display them all.

  • Chriztian Steinmeier 2793 posts 8776 karma points MVP 7x admin c-trib
    May 16, 2012 @ 22:55
    Chriztian Steinmeier

    Hi mfeola,

    To access an element by name (when you don't know the name beforehand) you can use the name() function:

    <xsl:for-each select="$currentPage/*[name() = $ListField]/data/item">


  • mfeola 117 posts 221 karma points
    May 17, 2012 @ 16:56

    that works perfectly, just had to change the macro from accepting the field to accepting the field name, thank you :D

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