Hi,

I used this awesome package for a new website, but I have som difficulties setting up a link.

In the mediatype I placed the following:

Name: Link to page
Alias: slideshowLink
Type: Content Picker
Tab: Content

When I choose to create a new media, I choose my new Mediatype "Slideshow", upload a picture and set a link.

Everything works fine except the link. Either I get a error or nothing appears when I try to place the information in XSLT.

Here is the XSLT document:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [  <!ENTITY nbsp "&#x00A0;">]>
<xsl:stylesheet
    version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets"
   exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets ">


<xsl:output method="xml" omit-xml-declaration="yes" />

<xsl:param name="currentPage"/>

<!-- Input the related links property alias here -->
<xsl:variable name="propertyAlias" select="string('frontSlideshow')"/>

<xsl:template match="/">

<!-- The fun starts here -->
<ul class="teaser">
    <xsl:for-each select="$currentPage/data [@alias = $propertyAlias]/links/link">
      <li>
            <div class="copy">
              <h1><xsl:value-of select="umbraco.library:GetMedia(./@link,0)/data[@alias='slideshowHeader']"/><br /><span class="thin"><xsl:value-of select="umbraco.library:GetMedia(./@link,0)/data[@alias='slideshowSubHeader']"/></span></h1>
              <p><xsl:value-of select="umbraco.library:GetMedia(./@link,0)/data[@alias='slideshowCopy']"/></p>
                <p><a href="WHAT CODE SHOULD BE INSERTED TO GET THE CONTENT PICKER LINK">THE PROBLEM IS RIGHT HERE!</a></p>
           </div>
          <span class="img_bg">
               <xsl:element name="img">
                    <xsl:attribute name="src">
                      <xsl:value-of select="umbraco.library:GetMedia(./@link,0)/data[@alias='umbracoFile']"/>
                 </xsl:attribute>
                    <xsl:attribute name="alt">
                      <xsl:value-of select="umbraco.library:GetMedia(./@link,0)/data[@alias='slideshowHeader']"/>
                 </xsl:attribute>
                </xsl:element>
          </span>
         <span class="fade_red"></span>
        </li>
   </xsl:for-each>
</ul>
<!-- Live Editing support for related links. -->
<xsl:value-of select="umbraco.library:Item($currentPage/@id,$propertyAlias,'')" />

</xsl:template>

</xsl:stylesheet>

Is there anyone who could tell me that magic code I need, to get a link working through a mediatype?

Kind regards,

Niels Kristiansen